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有机高分子材料的分类及鉴别

> 汽车的安全气囊中装有叠氮化钠（NaN 3），受到强烈撞击时发生分解，其化学方程式为：2NaN 3 == 2Na + 3N 2↑,气囊的体积迅速膨胀，达到保护驾乘人员的目的。请计算，要产生42 g氮气，理论上需要多少克叠氮化钠分解？

问题：

发布时间：2024-09-09

汽车的安全气囊中装有叠氮化钠（NaN ₃），受到强烈撞击时发生分解，其化学方程式为：2NaN _{3 ==}2Na + 3N ₂↑,气囊的体积迅速膨胀，达到保护驾乘人员的目的。请计算，要产生42 g氮气，理论上需要多少克叠氮化钠分解？

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