问题：
计算：
(1-
1
22
)×(1-
1
32
)=______；
(1-
1
22
)×(1-
1
32
)×(1-
1
42
)=______；
(1-
1
22
)×(1-
1
32
)×…×(1-
1
92
)×(1-
1
102
)=______；
(1-
1
22
)×(1-
1
32
)×…×(1-
1
(n-1)2
)×(1-
1
n2
)=______．
计算：
(1-
)×(1-
)=______；
(1-
)×(1-
)×(1-
)=______；
(1-
)×(1-
)×…×(1-
)×(1-
)=______；
(1-
)×(1-
)×…×(1-
)×(1-
)=______．
(1-
| 1 |
| 22 |
| 1 |
| 32 |
(1-
| 1 |
| 22 |
| 1 |
| 32 |
| 1 |
| 42 |
(1-
| 1 |
| 22 |
| 1 |
| 32 |
| 1 |
| 92 |
| 1 |
| 102 |
(1-
| 1 |
| 22 |
| 1 |
| 32 |
| 1 |
| (n-1)2 |
| 1 |
| n2 |
参考答案：