问题:
解方程
(1)(x-3) 2+2x(x-3)=0;
(2)x 2-4x+1=0(用配方法);
(3)(x+2)(x+3)=20;
(4)
1
x
=
x
3x-2
.
解方程
(1)(x-3) 2+2x(x-3)=0;
(2)x 2-4x+1=0(用配方法);
(3)(x+2)(x+3)=20;
(4)
=
.
(1)(x-3) 2+2x(x-3)=0;
(2)x 2-4x+1=0(用配方法);
(3)(x+2)(x+3)=20;
(4)
1 |
x |
x |
3x-2 |
参考答案: