问题:
用换元法解方程
x-2
x2
+
2x2
x-2
=3时,设
x-2
x2
=y,则原方程可变形为( )
A.y2-3y+2=0
B.2y2-3y+1=0
C.y2+3y-2=0
D.2y2+3y-1=0
用换元法解方程
+
=3时,设
=y,则原方程可变形为( )
x-2 |
x2 |
2x2 |
x-2 |
x-2 |
x2 |
A.y2-3y+2=0 | B.2y2-3y+1=0 | C.y2+3y-2=0 | D.2y2+3y-1=0 |
参考答案: