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函数的零点

> 已知函数 f(x)=sin2x+2 3 sinxcosx- 1 2 cos2x，x∈R．（I）求f（x）的最小正周期和值域；（II）若 x0(0≤x0≤ π 2 )为f（x）的一个零点，求sin2x 0的值．

问题：

发布时间：2024-09-10

已知函数 f(x)=sin2x+2

3

sinxcosx-

1

2

cos2x，x∈R．
（I）求f（x）的最小正周期和值域；
（II）若 x0(0≤x0≤

π

2

)为f（x）的一个零点，求sin2x ₀的值．

参考答案：

提问用户：kD***K2l

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已知函数 f(x)=sin2x+2 3 sinxcosx- 1 2 cos2x，x∈R． （I）求f（x）的最小正周期和值域； （II）若 x0(0≤x0≤ π 2 )为f（x）的一个零点，求sin2x 0的值．

可能感兴趣的题目：

已知函数 f(x)=sin2x+2

3

sinxcosx-

1

2

cos2x，x∈R．
（I）求f（x）的最小正周期和值域；
（II）若 x0(0≤x0≤

π

2

)为f（x）的一个零点，求sin2x ₀的值．