问题:
曲线y=ax 3+bx-1在点(1,f(1))处的切线方程为y=x,则b-a=
[ ]
A.-3
B.2
C.3
D.4
曲线y=ax 3+bx-1在点(1,f(1))处的切线方程为y=x,则b-a=
B.2
C.3
D.4
[ ]
A.-3 B.2
C.3
D.4
参考答案: