问题:

 如图,已知∠A=∠F,∠C=∠D,试说明BD∥CE.
解:∵∠A=∠F(已知)
∴AC∥DF(                                                )
∴∠D=∠ (     ) (                                        )
又∵∠C=∠D(已知)
∴∠1=∠C(等量代换)
∴BD∥CE(                                              )

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