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> 不定项选择在竖直方向的电场中固定一个质量为m、电荷量为+q的小球，场强E的变化规律如图所示，以竖直向上为场强的正方向，E 0=2mg/q，t（0≤t＜T）时刻释放小球，在t～t+T时间内合力的冲量大小为（） A．0 B．mgT C．3mgT/2 D．2mgT

问题：

发布时间：2024-09-07

不定项选择在竖直方向的电场中固定一个质量为m、电荷量为+q的小球，场强E的变化规律如图所示，以竖直向上为场强的正方向，E ₀=2mg/q，t（0≤t＜T）时刻释放小球，在t～t+T时间内合力的冲量大小为（）
A．0
B．mgT
C．3mgT/2
D．2mgT

参考答案：

提问用户：8i***xu7

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