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> 设函数f（x）=2cos 2x+sin2x+a（a∈R）．（1）求函数f（x）的最小正周期和单调递增区间；（2）当 x∈[0， π 6 ]时，f（x）的最大值为2，求a的值，并求出y=f（x）（x∈R）的对称轴方程．

问题：

发布时间：2024-09-08

设函数f（x）=2cos ²x+sin2x+a（a∈R）．
（1）求函数f（x）的最小正周期和单调递增区间；
（2）当 x∈[0，

π

6

]时，f（x）的最大值为2，求a的值，并求出y=f（x）（x∈R）的对称轴方程．

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设函数f（x）=2cos 2x+sin2x+a（a∈R）． （1）求函数f（x）的最小正周期和单调递增区间； （2）当 x∈[0， π 6 ]时，f（x）的最大值为2，求a的值，并求出y=f（x）（x∈R）的对称轴方程．

可能感兴趣的题目：

设函数f（x）=2cos ²x+sin2x+a（a∈R）．
（1）求函数f（x）的最小正周期和单调递增区间；
（2）当 x∈[0，

π

6

]时，f（x）的最大值为2，求a的值，并求出y=f（x）（x∈R）的对称轴方程．