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> 函数y=cos 2ωx-sin 2ωx（ω＞0）的最小正周期是π，则函数f（x）=2sin（ωx+ π 4 ）的一个单调递增区间是（　　） A．[- π 2 ， π 2 ] B．[- 5π 4 ， 9π 4 ] C．[- π 4 ， 3π 4 ] D．[ π 4 ， 5π 4 ]

问题：

发布时间：2024-09-08

函数y=cos ²ωx-sin ²ωx（ω＞0）的最小正周期是π，则函数f（x）=2sin（ωx+

π

4

）的一个单调递增区间是（　　）

A．[-

π

2

，

π

2

] B．[-

5π

4

，

9π

4

] C．[-

π

4

，

3π

4

] D．[

π

4

，

5π

4

]

参考答案：

提问用户：wO***N8J

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函数y=cos 2ωx-sin 2ωx（ω＞0）的最小正周期是π，则函数f（x）=2sin（ωx+ π 4 ）的一个单调递增区间是（ ） A．[- π 2 ， π 2 ] B．[- 5π 4 ， 9π 4 ] C．[- π 4 ， 3π 4 ] D．[ π 4 ， 5π 4 ]

可能感兴趣的题目：

函数y=cos ²ωx-sin ²ωx（ω＞0）的最小正周期是π，则函数f（x）=2sin（ωx+

π

4

）的一个单调递增区间是（　　）

A．[-

π

2

，

π

2

] B．[-

5π

4

，

9π

4

] C．[-

π

4

，

3π

4

] D．[

π

4

，

5π

4

]