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> 设函数f（x）=（sinωx+cosωx） 2+2cos 2ωx（ω＞0）的最小正周期为 2π 3 ．（Ⅰ）求ω的值；（Ⅱ）若函数y=g（x）的图象是由y=f（x）的图象向右平移 π 2 个单位长度得到，求y=g（x）的单调增区间．

问题：

发布时间：2024-09-10

设函数f（x）=（sinωx+cosωx） ²+2cos ²ωx（ω＞0）的最小正周期为

2π

3

．
（Ⅰ）求ω的值；
（Ⅱ）若函数y=g（x）的图象是由y=f（x）的图象向右平移

π

2

个单位长度得到，求y=g（x）的单调增区间．

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设函数f（x）=（sinωx+cosωx） 2+2cos 2ωx（ω＞0）的最小正周期为 2π 3 ． （Ⅰ）求ω的值； （Ⅱ）若函数y=g（x）的图象是由y=f（x）的图象向右平移 π 2 个单位长度得到，求y=g（x）的单调增区间．

可能感兴趣的题目：

设函数f（x）=（sinωx+cosωx） ²+2cos ²ωx（ω＞0）的最小正周期为

2π

3

．
（Ⅰ）求ω的值；
（Ⅱ）若函数y=g（x）的图象是由y=f（x）的图象向右平移

π

2

个单位长度得到，求y=g（x）的单调增区间．