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> 设函数 f(x)=acos2(ωx)- 3 asin(ωx)cos(ωx)+b 的最小正周期为π（a≠0，ω＞0）（1）求ω的值；（2）若f（x）的定义域为 [- π 3 ， π 6 ]，值域为[-1，5]，求a，b的值及单调区间．

问题：

发布时间：2024-09-13

设函数 f(x)=acos2(ωx)-

3

asin(ωx)cos(ωx)+b
的最小正周期为π（a≠0，ω＞0）
（1）求ω的值；
（2）若f（x）的定义域为 [-

π

3

，

π

6

]，值域为[-1，5]，求a，b的值及单调区间．

参考答案：

提问用户：2O***56q

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设函数 f(x)=acos2(ωx)- 3 asin(ωx)cos(ωx)+b 的最小正周期为π（a≠0，ω＞0） （1）求ω的值； （2）若f（x）的定义域为 [- π 3 ， π 6 ]，值域为[-1，5]，求a，b的值及单调区间．

可能感兴趣的题目：

设函数 f(x)=acos2(ωx)-

3

asin(ωx)cos(ωx)+b
的最小正周期为π（a≠0，ω＞0）
（1）求ω的值；
（2）若f（x）的定义域为 [-

π

3

，

π

6

]，值域为[-1，5]，求a，b的值及单调区间．