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任意角三角函数的概念

> θ是第二象限角，且满足cos θ 2 -sin θ 2 = (sin θ 2 -cos θ 2 )2 ，那么 θ 2 （　　） A．是第一象限角 B．是第二象限角 C．是第三象限角 D．可能是第一象限角，也可能是第三象限角

问题：

发布时间：2024-09-12

θ是第二象限角，且满足cos

θ

2

-sin

θ

2

=

(sin

θ

2

-cos

θ

2

)2

，那么

θ

2

（　　）

A．是第一象限角

B．是第二象限角

C．是第三象限角

D．可能是第一象限角，也可能是第三象限角

参考答案：

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θ是第二象限角，且满足cos θ 2 -sin θ 2 = (sin θ 2 -cos θ 2 )2 ，那么 θ 2 （ ） A．是第一象限角 B．是第二象限角 C．是第三象限角 D．可能是第一象限角，也可能是第三象限角

可能感兴趣的题目：

θ是第二象限角，且满足cos

θ

2

-sin

θ

2

=

(sin

θ

2

-cos

θ

2

)2

，那么

θ

2

（　　）

A．是第一象限角

B．是第二象限角

C．是第三象限角

D．可能是第一象限角，也可能是第三象限角