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氯及其化合物

> (6分）把含硫酸铵和硝酸铵的混合液a L分成两等份。一份加入bmol NaOH并加热，恰好把NH 3全部赶出，另一份需消耗cmol BaCl 2沉淀反应恰好完全，试计算：原混合溶液中含有的NH 4 +为 mol；原溶液中NO 3 - 的浓度为 mol/L

问题：

发布时间：2024-09-13

(6分）把含硫酸铵和硝酸铵的混合液a L分成两等份。一份加入bmol NaOH并加热，恰好把NH ₃全部赶出，另一份需消耗cmol BaCl ₂沉淀反应恰好完全，试计算：
原混合溶液中含有的NH ₄ ⁺为 mol；
原溶液中NO ₃ ^-的浓度为 mol/L

参考答案：

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(6分）把含硫酸铵和硝酸铵的混合液a L分成两等份。一份加入bmol NaOH并加热，恰好把NH 3全部赶出，另一份需消耗cmol BaCl 2沉淀反应恰好完全，试计算： 原混合溶液中含有的NH 4 +为 mol； 原溶液中NO 3 - 的浓度为 mol/L

可能感兴趣的题目：

(6分）把含硫酸铵和硝酸铵的混合液a L分成两等份。一份加入bmol NaOH并加热，恰好把NH ₃全部赶出，另一份需消耗cmol BaCl ₂沉淀反应恰好完全，试计算：
原混合溶液中含有的NH ₄ ⁺为 mol；
原溶液中NO ₃ ^-的浓度为 mol/L