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> 某溶液中大量存在以下五种离子：NO 3 -、SO 4 2-、Fe 3+、H +、M，其物质的量之比为n（NO 3 -）：n（SO 4 2-）：n（Fe 3+）：n（H +）：n（M）=2：3：1：3：1，则M可能为（　　） A．Mg2+ B．Fe2+ C．CO32- D．Ba2+

问题：

发布时间：2024-09-12

某溶液中大量存在以下五种离子：NO ₃ ^-、SO ₄ ^2-、Fe ³⁺、H ⁺、M，其物质的量之比为n（NO ₃ ^-）：n（SO ₄ ^2-）：n（Fe ³⁺）：n（H ⁺）：n（M）=2：3：1：3：1，则M可能为（　　）

A．Mg²⁺ B．Fe²⁺ C．CO₃^2- D．Ba²⁺

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提问用户：Bg***3u2

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某溶液中大量存在以下五种离子：NO 3 -、SO 4 2-、Fe 3+、H +、M，其物质的量之比为n（NO 3 -）：n（SO 4 2-）：n（Fe 3+）：n（H +）：n（M）=2：3：1：3：1，则M可能为（ ） A．Mg2+ B．Fe2+ C．CO32- D．Ba2+

可能感兴趣的题目：

某溶液中大量存在以下五种离子：NO ₃ ^-、SO ₄ ^2-、Fe ³⁺、H ⁺、M，其物质的量之比为n（NO ₃ ^-）：n（SO ₄ ^2-）：n（Fe ³⁺）：n（H ⁺）：n（M）=2：3：1：3：1，则M可能为（　　）

A．Mg²⁺ B．Fe²⁺ C．CO₃^2- D．Ba²⁺