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> 某溶液中有NH 4 +、Mg 2+、Fe 2+和Al 3+四种离子，若向其中加入过量的氢氧化钠溶液，微热并搅拌，再加入过量盐酸，溶液中大量减少的阳离子是（　　） A．NH4+ B．Mg2+ C．Fe2+ D．Al3+

问题：

发布时间：2024-09-09

某溶液中有NH ₄ ⁺、Mg ²⁺、Fe ²⁺和Al ³⁺四种离子，若向其中加入过量的氢氧化钠溶液，微热并搅拌，再加入过量盐酸，溶液中大量减少的阳离子是（　　）

A．NH₄⁺ B．Mg²⁺ C．Fe²⁺ D．Al³⁺

参考答案：

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某溶液中有NH 4 +、Mg 2+、Fe 2+和Al 3+四种离子，若向其中加入过量的氢氧化钠溶液，微热并搅拌，再加入过量盐酸，溶液中大量减少的阳离子是（ ） A．NH4+ B．Mg2+ C．Fe2+ D．Al3+

可能感兴趣的题目：

某溶液中有NH ₄ ⁺、Mg ²⁺、Fe ²⁺和Al ³⁺四种离子，若向其中加入过量的氢氧化钠溶液，微热并搅拌，再加入过量盐酸，溶液中大量减少的阳离子是（　　）

A．NH₄⁺ B．Mg²⁺ C．Fe²⁺ D．Al³⁺