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氯及其化合物

> 实验室可用如下反应制取氯气，反应原理如下： 2KMnO 4 ＋ 16HCl ＝ 2KCl ＋ 2MnCl 2＋ 5Cl 2↑ ＋ 8H 2O （1）用单线桥表示出上述反应中电子转移的方向和数目（2）上述反应中氧化剂与还原剂的物质的量比（3）15.8g KMnO 4能使多少克HCl被氧化？（4）产生的Cl 2在标准状况下的体积为多少？（

问题：

发布时间：2024-09-07

实验室可用如下反应制取氯气，反应原理如下：
2KMnO ₄＋ 16HCl ＝ 2KCl ＋ 2MnCl ₂＋ 5Cl ₂↑ ＋ 8H ₂O
（1）用单线桥表示出上述反应中电子转移的方向和数目
（2）上述反应中氧化剂与还原剂的物质的量比
（3）15.8g KMnO ₄能使多少克HCl被氧化？
（4）产生的Cl ₂在标准状况下的体积为多少？（

参考答案：

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